Each row is one life. It’s important to know that Mario played the same level each time because he died on his first four lives. This means that each of the first four rows must have exactly one (D)eath, and the last row cannot have any. X’s, which indicate that Mario did not even make it to that part of the level, only occur after (D)eaths, so there are none in the bottom row, but any cell to the right of the (D)eath in the other rows must be X.
L5:P5 gives you L1:P4 as (U)nhurt.
Since the directions state that Mario died on his first four lives, he had to die on life 1 at some point. Since he survived the second last part, he must have died on the last part, so L1:P5 is (D)ied.
L1:P5 tells you that nowhere in the middle column did Mario survive unhurt. But you know Mario was alive during part 3 on both life 1 and life 5, so L1:P3 and L5:P3 must both be (H)urt, but made it.
L1:P3 tells you that there cannot be three (H)urt but made it in a row. You know that Mario was alive at L5:P4, so it must be (U)nhurt.
L5:P3 tells you that at least two parts on life 3 were unhurt.You know it’s not L3:P3 from L1:P5. You know it’s not L3:P5 because Mario didn’t survive the whole level on life 3. It also cannot be L3:P4 because L5:P4 tells you that no death occurs right after unhurt except for the instance in life 1. So if L3:P4 were to be unhurt, L3:P5 could not be death, and again, Mario would survive life 3. So the only two possibilities for (U)nhurt on life 3 are L3:P1 and L3:P2
L3:P3 is not death, according to L5:P4. It is also not unhurt, according to L1:P5. It cannot be X because Mario hasn’t died yet on that life, so L3:P3 must be (H)urt, but made it.
One scenario L3:P3 offers is that one of the parts had the same status on all five lives. L1:P4 says that Mario died on part 1 on one of his lives, so part 1 can’t be the same on all five lives. The fact that part 1 has a death on one of the lives means that same life has X’s on parts 2-5. Clearly no part can be X’s all the way down, so you know that no part had the same status on all five lives. This means, according to L3:P3, that L2:P3 is either hurt or died. That means Mario was alive at least until then in that life. This means the only life in which Mario could have died in part 1 (L1:P4) is life 4. So L4:P1 is (D)ied.
Any spots to the right of a death within a life must be X. So L4:P2-5 are X.
You know Mario dies in part 5 on life 1 and doesn’t die at all on life 5. So L1:P1, L1: P2, L5:P1, and L5:P2 are all either hurt or unhurt. L4:P5 tells you that life 1 and life 5 were not both unhurt at part 1 or part 2 because life 3 is unhurt at both those parts. But those four parts cannot all be hurt, but made it either, according to L1:P3. This means that they are opposite and alternating. That is, life 1 or life 5 starts hurt, then unhurt, and the other one starts unhurt, then hurt. All this means that you already have two unhurts in both part 1 and part 2. So L2:P1 and L2:P2 cannot be unhurt, according to L4:P5. You know from L3:P3 that Mario was alive on life 3 at least until part 3. So L2:P1 and L2:P2 are both (H)urt, but made it.
L1:P5 (orL3:P3) tells you that L2:P3 is either hurt or died. But according to L1:P3, it cannot be hurt, but made it, so L2:P3 is (D)ied.
After any death are only X’s, so L2:P4 and L2:P5 are X.
You established in step 14/25 above that life 1 or life 5 starts hurt, then unhurt, and the other one starts unhurt, then hurt. Since both life 1 and life 5 were hurt at part 3, one of them will have two hurts in a row. There are also two hurts in a row in life 2. So according to L2:P4, no other life can have two hurts in a row. This means L3:P4 is not hurt, but made it. It also cannot be unhurt, because L5:P4 says that he couldn’t have died in L3:P5 if L3:P4 is unhurt, but Mario did die on life 3. So L3:P4 must be (D)ied.
L3:P5, of course, is X.
Mario couldn’t have died twice on the same life, so L3:P5 is clearly referring to life 5. So L5:P1 is (H)urt, but made it.
According to L1:P3, L5:P2 cannot be hurt, so it is (U)nhurt.
According to L4:P5, L1:P2 cannot be unhurt, so it is (H)urt, but made it.
According to L1:P3, L1:P1 cannot be hurt, so it is (U)nhurt.