1.) For a road to go for 3 straight east/west units, something in Column C must be one of them. So according to A3, either C4 or C6 (or both) is (r)oad. However, C5 tells you that C6 is a place with doors. That certainly rules out (w)ater and (r)oad. Therefore C4 is (r)oad.
2.) C4 tells you that both E3 and E4 are (h)ousing.
3.) Now that you have placed E4 and it is not road, B4 must be (r)oad according to A3.
4.) B4 is clearly an intersection of 2 roads. Therefore, according to E3, Quality Rd must also be at B3 and/or B5. But according to E4, B5 is either (a)ttraction or (s)tore. Therefore B3 must be (r)oad.
5.) B5 is not (r)oad according to E4. C6 is not road according to C5. Therefore, according to B3, D5 must be Inferior Way, that is, (r)oad.
6.) D5 tells you that A4 is not (s)tore, since it is next to an intersection, B4. This means, according to A3, that D4 must be (r)oad.
6.) D5 tells you that B5 is not (s)tore, since it is next to an intersection, B4. This means, according to E4, that B5 is mini golf, that is, (a)ttraction.
7.) D5 tells you that A4 is not (r)oad. According to E3 and B5, no remaining cell can be road except cells in Column B and Column D. This means that the boat shop referred to in D4 ( (s)tores must be next to (r)oad) must be at C6, D6, E5, or E6, since it is south of Row 4. The boat shop also cannot be next to a school, so it actually cannot be C6. C6 cannot be (w)ater according to C5, so if the boat shop is D6, the (w)ater next to it would have to be E6. If the boat shop is at E5, the (w)ater next to it would also have to be E6. If the boat shop is E6, D6 would need to be road, since every (s)tore is next to a road (D5) and E5 can’t be (r)oad, according to the beginning of this step. So if the boat shop is E6, D6 is (r)oad and the (w)ater next to the boat shop would be E5. However, B4 tells you that E4 cannot have (w)ater next to it. Therefore the boat shop is at either E5 or D6. Either way, the (w)ater next to it is E6.
8.) E6 tells you that D3 and/or D6 is (r)oad, and that B2 is (r)oad for sure.
9.) Homestead Village is next to 3 cells, one of them being E4, which is (h)ousing. Therefore, according to B2, both D3 and E2 are (a)ttraction.
10.) According to E6, D6 is (r)oad.
11.) According to D4 and step 7 above, E5 is (s)tore.
11.) D6 refers to a cell that is next to 4 cells. Only the center 12 cells are next to 4 cells, and 9 of them are already known. So “that fishing lake” must be C2, C3, or D2. Of those, only D2 can meet the requirements of D6, so D2 is (w)ater.
12.) According to D6 and D5 and the fact that the only possible remaining (r)oad cell is B1, C2 must be (s)tore.
13.) According to D6, D1 must be (e)ducational institution.
14.) All the things in D1 are already known. The 1 (h)ousing is E4. The 1 (e)ducational is C5. The 1 (a)ttraction is D3. C6 is next to Inferior Way, so C6 cannot be (h)ousing, (e)ducational, or (a)ttraction. It also is a place with doors according to C5, meaning it is not (w)ater or (r)oad. Therefore C6 must be (s)tore.
15.) 2 water cells are known. E5 says that there are only 2 more, and both are in Rows 5 and 6. According to B4, an unplaced (h)ousing unit must be next to water, and it must be one of these 2 yet unknown (w)aters, since the 2 known (w)aters are not next to (h)ousing. But E2 indicates that A4 is not the (h)ousing that is next to water. All this means that A5, A6, and B6 must contain some combination of 2 (w)aters and 1 (h)ousing. But according to C2, B6 cannot be (h)ousing. Therefore B6 must be (w)ater.
16.) According to B6, A4 is (h)ousing.
17.) According to step 15 above, A5 and A6 are some combination of (w)ater and (h)ousing. But if A5 is (w)ater, 2 (h)ousing units are next to (w)ater, which violates B4. Therefore A5 is (h)ousing and A6 is (w)ater.
18.) According to A5, B1 is (r)oad.
19.) The only 2 adjacent cells that are both unknown are A1 and A2. Therefore, according A4, they are both (a)ttraction.
20.) A1 tells you that C1 or C3 is (e)ducational. A2 tells you that C1 or C3 is (a)ttraction. A6 tells you that C1, C3, or E1 is (h)ousing. Therefore E1 is (h)ousing.
21. E1 and A1 tell you that C1 is (e)ducational.
22.) A2 tells you that C3 is (a)ttraction.